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250011379873 is a prime number
BaseRepresentation
bin1110100011010111010…
…1101110100010100001
3212220022201112000101001
43220311311232202201
513044010403123443
6310504215312001
724030341444143
oct3506565564241
9786281460331
10250011379873
11970359a7102
124055437b601
131a764544848
14c15a134c93
156783d15d4d
hex3a35d6e8a1

250011379873 has 2 divisors, whose sum is σ = 250011379874. Its totient is φ = 250011379872.

The previous prime is 250011379837. The next prime is 250011379909. The reversal of 250011379873 is 378973110052.

Together with previous prime (250011379837) it forms an Ormiston pair, because they use the same digits, order apart.

It is a balanced prime because it is at equal distance from previous prime (250011379837) and next prime (250011379909).

It can be written as a sum of positive squares in only one way, i.e., 249887012769 + 124367104 = 499887^2 + 11152^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-250011379873 is a prime.

It is a super-2 number, since 2×2500113798732 (a number of 24 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (250011379823) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 125005689936 + 125005689937.

It is an arithmetic number, because the mean of its divisors is an integer number (125005689937).

Almost surely, 2250011379873 is an apocalyptic number.

It is an amenable number.

250011379873 is a deficient number, since it is larger than the sum of its proper divisors (1).

250011379873 is an equidigital number, since it uses as much as digits as its factorization.

250011379873 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 317520, while the sum is 46.

The spelling of 250011379873 in words is "two hundred fifty billion, eleven million, three hundred seventy-nine thousand, eight hundred seventy-three".