250011545052133 has 2 divisors, whose sum is σ = 250011545052134. Its totient is φ = 250011545052132.

The previous prime is 250011545052109. The next prime is 250011545052187. The reversal of 250011545052133 is 331250545110052.

250011545052133 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 247825739520324 + 2185805531809 = 15742482^2 + 1478447^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-250011545052133 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 250011545052092 and 250011545052101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (250011545055133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 125005772526066 + 125005772526067.

It is an arithmetic number, because the mean of its divisors is an integer number (125005772526067).

Almost surely, 2^{250011545052133} is an apocalyptic number.

It is an amenable number.

250011545052133 is a deficient number, since it is larger than the sum of its proper divisors (1).

250011545052133 is an equidigital number, since it uses as much as digits as its factorization.

250011545052133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 90000, while the sum is 37.

The spelling of 250011545052133 in words is "two hundred fifty trillion, eleven billion, five hundred forty-five million, fifty-two thousand, one hundred thirty-three".