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250012435104197 is a prime number
BaseRepresentation
bin111000110110001010001110…
…011000100100000111000101
31012210012221210110122001210222
4320312022032120210013011
5230232200431341313242
62243422043242154125
7103442542131502013
oct7066121630440705
91183187713561728
10250012435104197
1172730750895257
122405a1027b2945
13a9670c102927c
1445a494894b8b3
151dd85e57695d2
hexe3628e6241c5

250012435104197 has 2 divisors, whose sum is σ = 250012435104198. Its totient is φ = 250012435104196.

The previous prime is 250012435104191. The next prime is 250012435104227. The reversal of 250012435104197 is 791401534210052.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 146921695507876 + 103090739596321 = 12121126^2 + 10153361^2 .

It is a cyclic number.

It is not a de Polignac number, because 250012435104197 - 212 = 250012435100101 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (250012435104191) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 125006217552098 + 125006217552099.

It is an arithmetic number, because the mean of its divisors is an integer number (125006217552099).

Almost surely, 2250012435104197 is an apocalyptic number.

It is an amenable number.

250012435104197 is a deficient number, since it is larger than the sum of its proper divisors (1).

250012435104197 is an equidigital number, since it uses as much as digits as its factorization.

250012435104197 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 302400, while the sum is 44.

The spelling of 250012435104197 in words is "two hundred fifty trillion, twelve billion, four hundred thirty-five million, one hundred four thousand, one hundred ninety-seven".