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2500142807 is a prime number
BaseRepresentation
bin1001010100000101…
…0010011011010111
320110020110102011202
42111001102123113
520110014032212
61052030423115
7115645602041
oct22501223327
96406412152
102500142807
1110732a1328
12599361a9b
1330ac7c456
1419a08aa91
15e97580c2
hex950526d7

2500142807 has 2 divisors, whose sum is σ = 2500142808. Its totient is φ = 2500142806.

The previous prime is 2500142773. The next prime is 2500142819. The reversal of 2500142807 is 7082410052.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 2500142807 - 216 = 2500077271 is a prime.

It is a super-3 number, since 3×25001428073 (a number of 29 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 2500142807.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2500142837) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1250071403 + 1250071404.

It is an arithmetic number, because the mean of its divisors is an integer number (1250071404).

Almost surely, 22500142807 is an apocalyptic number.

2500142807 is a deficient number, since it is larger than the sum of its proper divisors (1).

2500142807 is an equidigital number, since it uses as much as digits as its factorization.

2500142807 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4480, while the sum is 29.

The square root of 2500142807 is about 50001.4280496067. The cubic root of 2500142807 is about 1357.2346503278.

Adding to 2500142807 its reverse (7082410052), we get a palindrome (9582552859).

The spelling of 2500142807 in words is "two billion, five hundred million, one hundred forty-two thousand, eight hundred seven".