Base | Representation |
---|---|
bin | 1001010100000101… |
… | …0010011011010111 |
3 | 20110020110102011202 |
4 | 2111001102123113 |
5 | 20110014032212 |
6 | 1052030423115 |
7 | 115645602041 |
oct | 22501223327 |
9 | 6406412152 |
10 | 2500142807 |
11 | 10732a1328 |
12 | 599361a9b |
13 | 30ac7c456 |
14 | 19a08aa91 |
15 | e97580c2 |
hex | 950526d7 |
2500142807 has 2 divisors, whose sum is σ = 2500142808. Its totient is φ = 2500142806.
The previous prime is 2500142773. The next prime is 2500142819. The reversal of 2500142807 is 7082410052.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 2500142807 - 216 = 2500077271 is a prime.
It is a super-3 number, since 3×25001428073 (a number of 29 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 2500142807.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2500142837) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1250071403 + 1250071404.
It is an arithmetic number, because the mean of its divisors is an integer number (1250071404).
Almost surely, 22500142807 is an apocalyptic number.
2500142807 is a deficient number, since it is larger than the sum of its proper divisors (1).
2500142807 is an equidigital number, since it uses as much as digits as its factorization.
2500142807 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 4480, while the sum is 29.
The square root of 2500142807 is about 50001.4280496067. The cubic root of 2500142807 is about 1357.2346503278.
Adding to 2500142807 its reverse (7082410052), we get a palindrome (9582552859).
The spelling of 2500142807 in words is "two billion, five hundred million, one hundred forty-two thousand, eight hundred seven".
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