Base | Representation |
---|---|
bin | 100100011000100010101… |
… | …011010001001001011111 |
3 | 22212000120220121210010212 |
4 | 210120202223101021133 |
5 | 311431004144442142 |
6 | 5152333353123035 |
7 | 345431410404365 |
oct | 44304253211137 |
9 | 8760526553125 |
10 | 2500252734047 |
11 | 88439553a0a2 |
12 | 3446956b947b |
13 | 151a07b71103 |
14 | 890274a1635 |
15 | 45085dd4d82 |
hex | 24622ad125f |
2500252734047 has 2 divisors, whose sum is σ = 2500252734048. Its totient is φ = 2500252734046.
The previous prime is 2500252734043. The next prime is 2500252734073. The reversal of 2500252734047 is 7404372520052.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2500252734047 - 22 = 2500252734043 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2500252733995 and 2500252734013.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2500252734043) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1250126367023 + 1250126367024.
It is an arithmetic number, because the mean of its divisors is an integer number (1250126367024).
Almost surely, 22500252734047 is an apocalyptic number.
2500252734047 is a deficient number, since it is larger than the sum of its proper divisors (1).
2500252734047 is an equidigital number, since it uses as much as digits as its factorization.
2500252734047 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 470400, while the sum is 41.
The spelling of 2500252734047 in words is "two trillion, five hundred billion, two hundred fifty-two million, seven hundred thirty-four thousand, forty-seven".
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