Base | Representation |
---|---|
bin | 10111010010010001… |
… | …111011000001100001 |
3 | 2101112111002022011121 |
4 | 113102101323001201 |
5 | 402201201000144 |
6 | 15252555412241 |
7 | 1543406604004 |
oct | 272221730141 |
9 | 71474068147 |
10 | 25002750049 |
11 | a6704451a2 |
12 | 4a19454081 |
13 | 2485c8a174 |
14 | 12d28a153b |
15 | 9b5067384 |
hex | 5d247b061 |
25002750049 has 2 divisors, whose sum is σ = 25002750050. Its totient is φ = 25002750048.
The previous prime is 25002750043. The next prime is 25002750079. The reversal of 25002750049 is 94005720052.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12801338449 + 12201411600 = 113143^2 + 110460^2 .
It is a cyclic number.
It is not a de Polignac number, because 25002750049 - 23 = 25002750041 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 25002749996 and 25002750023.
It is not a weakly prime, because it can be changed into another prime (25002750041) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12501375024 + 12501375025.
It is an arithmetic number, because the mean of its divisors is an integer number (12501375025).
Almost surely, 225002750049 is an apocalyptic number.
It is an amenable number.
25002750049 is a deficient number, since it is larger than the sum of its proper divisors (1).
25002750049 is an equidigital number, since it uses as much as digits as its factorization.
25002750049 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 25200, while the sum is 34.
The spelling of 25002750049 in words is "twenty-five billion, two million, seven hundred fifty thousand, forty-nine".
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