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250042420050373 is a prime number
BaseRepresentation
bin111000110110100110001001…
…101000000011100111000101
31012210022211012011121011020001
4320312212021220003213011
5230233143334013102443
62243443522455441301
7103444653156362116
oct7066461150034705
91183284164534201
10250042420050373
1172742438587105
1224063a90686231
13a969b8c250382
1445a6190d9820d
151dd929cdbcd4d
hexe36989a039c5

250042420050373 has 2 divisors, whose sum is σ = 250042420050374. Its totient is φ = 250042420050372.

The previous prime is 250042420050301. The next prime is 250042420050433. The reversal of 250042420050373 is 373050024240052.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 221584868318529 + 28457551731844 = 14885727^2 + 5334562^2 .

It is a cyclic number.

It is not a de Polignac number, because 250042420050373 - 217 = 250042419919301 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (250042420057373) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 125021210025186 + 125021210025187.

It is an arithmetic number, because the mean of its divisors is an integer number (125021210025187).

Almost surely, 2250042420050373 is an apocalyptic number.

It is an amenable number.

250042420050373 is a deficient number, since it is larger than the sum of its proper divisors (1).

250042420050373 is an equidigital number, since it uses as much as digits as its factorization.

250042420050373 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 201600, while the sum is 37.

The spelling of 250042420050373 in words is "two hundred fifty trillion, forty-two billion, four hundred twenty million, fifty thousand, three hundred seventy-three".