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25004299241 is a prime number
BaseRepresentation
bin10111010010010111…
…110101001111101001
32101112121000000021002
4113102113311033221
5402202100033431
615253052524345
71543426015415
oct272227651751
971477000232
1025004299241
11a671303119
124a19a806b5
1324863b034c
1412d2b85d45
159b52713cb
hex5d25f53e9

25004299241 has 2 divisors, whose sum is σ = 25004299242. Its totient is φ = 25004299240.

The previous prime is 25004299217. The next prime is 25004299247. The reversal of 25004299241 is 14299240052.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 24994345216 + 9954025 = 158096^2 + 3155^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-25004299241 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 25004299195 and 25004299204.

It is not a weakly prime, because it can be changed into another prime (25004299247) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12502149620 + 12502149621.

It is an arithmetic number, because the mean of its divisors is an integer number (12502149621).

Almost surely, 225004299241 is an apocalyptic number.

It is an amenable number.

25004299241 is a deficient number, since it is larger than the sum of its proper divisors (1).

25004299241 is an equidigital number, since it uses as much as digits as its factorization.

25004299241 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 51840, while the sum is 38.

The spelling of 25004299241 in words is "twenty-five billion, four million, two hundred ninety-nine thousand, two hundred forty-one".