Base | Representation |
---|---|
bin | 111000111001100000001001… |
… | …100001001111100000000111 |
3 | 1012211000220200121002100011121 |
4 | 320321200021201033200013 |
5 | 230244431342331241320 |
6 | 2244115352140014411 |
7 | 103465253240121343 |
oct | 7071401141174007 |
9 | 1184026617070147 |
10 | 250242134243335 |
11 | 7280a102a88243 |
12 | 24096728531407 |
13 | a9829692a0950 |
14 | 45b1ad911c623 |
15 | 1dde58b1d88aa |
hex | e3980984f807 |
250242134243335 has 64 divisors (see below), whose sum is σ = 325360009175040. Its totient is φ = 183672035688960.
The previous prime is 250242134243327. The next prime is 250242134243407. The reversal of 250242134243335 is 533342431242052.
It is not a de Polignac number, because 250242134243335 - 23 = 250242134243327 is a prime.
It is a super-2 number, since 2×2502421342433352 (a number of 30 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 250242134243291 and 250242134243300.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 19877834221 + ... + 19877846809.
It is an arithmetic number, because the mean of its divisors is an integer number (5083750143360).
Almost surely, 2250242134243335 is an apocalyptic number.
250242134243335 is a deficient number, since it is larger than the sum of its proper divisors (75117874931705).
250242134243335 is a wasteful number, since it uses less digits than its factorization.
250242134243335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15488.
The product of its (nonzero) digits is 2073600, while the sum is 43.
Adding to 250242134243335 its reverse (533342431242052), we get a palindrome (783584565485387).
The spelling of 250242134243335 in words is "two hundred fifty trillion, two hundred forty-two billion, one hundred thirty-four million, two hundred forty-three thousand, three hundred thirty-five".
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