Base | Representation |
---|---|
bin | 1011011000011110111100… |
… | …10001000010011010111111 |
3 | 10021121220002211012001012011 |
4 | 11230033132101002122333 |
5 | 11240044432340121421 |
6 | 125122504325152051 |
7 | 5162252131534126 |
oct | 554173621023277 |
9 | 107556084161164 |
10 | 25030503442111 |
11 | 7a80416716092 |
12 | 29830b4b5b627 |
13 | 10c749bb2bb1b |
14 | 6276a8c5cabd |
15 | 2d617a4c94e1 |
hex | 16c3de4426bf |
25030503442111 has 2 divisors, whose sum is σ = 25030503442112. Its totient is φ = 25030503442110.
The previous prime is 25030503442099. The next prime is 25030503442129. The reversal of 25030503442111 is 11124430503052.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 25030503442111 - 215 = 25030503409343 is a prime.
It is a super-2 number, since 2×250305034421112 (a number of 28 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (25030503442151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12515251721055 + 12515251721056.
It is an arithmetic number, because the mean of its divisors is an integer number (12515251721056).
Almost surely, 225030503442111 is an apocalyptic number.
25030503442111 is a deficient number, since it is larger than the sum of its proper divisors (1).
25030503442111 is an equidigital number, since it uses as much as digits as its factorization.
25030503442111 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 25030503442111 its reverse (11124430503052), we get a palindrome (36154933945163).
The spelling of 25030503442111 in words is "twenty-five trillion, thirty billion, five hundred three million, four hundred forty-two thousand, one hundred eleven".
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