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2504033117 is a prime number
BaseRepresentation
bin1001010101000000…
…1000001101011101
320110111210001200022
42111100020031131
520112013024432
61052250041525
7116023634045
oct22520101535
96414701608
102504033117
111075509163
1259a7192a5
1330ba12101
1419a7c0725
15e9c75b12
hex9540835d

2504033117 has 2 divisors, whose sum is σ = 2504033118. Its totient is φ = 2504033116.

The previous prime is 2504033113. The next prime is 2504033131. The reversal of 2504033117 is 7113304052.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1467579481 + 1036453636 = 38309^2 + 32194^2 .

It is a cyclic number.

It is not a de Polignac number, because 2504033117 - 22 = 2504033113 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2504033113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1252016558 + 1252016559.

It is an arithmetic number, because the mean of its divisors is an integer number (1252016559).

Almost surely, 22504033117 is an apocalyptic number.

It is an amenable number.

2504033117 is a deficient number, since it is larger than the sum of its proper divisors (1).

2504033117 is an equidigital number, since it uses as much as digits as its factorization.

2504033117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2520, while the sum is 26.

The square root of 2504033117 is about 50040.3149170746. The cubic root of 2504033117 is about 1357.9382537684.

Adding to 2504033117 its reverse (7113304052), we get a palindrome (9617337169).

The spelling of 2504033117 in words is "two billion, five hundred four million, thirty-three thousand, one hundred seventeen".