Base | Representation |
---|---|
bin | 100100100001101001101… |
… | …011111010011100101111 |
3 | 22212221211120211121012021 |
4 | 210201221223322130233 |
5 | 312111022202121033 |
6 | 5201032124051011 |
7 | 346225661100436 |
oct | 44415153723457 |
9 | 8787746747167 |
10 | 2510034020143 |
11 | 88855484a111 |
12 | 346565393a67 |
13 | 152906451370 |
14 | 896b457011d |
15 | 4545998db2d |
hex | 24869afa72f |
2510034020143 has 32 divisors (see below), whose sum is σ = 2765690524800. Its totient is φ = 2263968645120.
The previous prime is 2510034020089. The next prime is 2510034020209. The reversal of 2510034020143 is 3410204300152.
It is a de Polignac number, because none of the positive numbers 2k-2510034020143 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (2510034029143) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 62829871 + ... + 62869807.
It is an arithmetic number, because the mean of its divisors is an integer number (86427828900).
Almost surely, 22510034020143 is an apocalyptic number.
2510034020143 is a deficient number, since it is larger than the sum of its proper divisors (255656504657).
2510034020143 is a wasteful number, since it uses less digits than its factorization.
2510034020143 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 40627.
The product of its (nonzero) digits is 2880, while the sum is 25.
Adding to 2510034020143 its reverse (3410204300152), we get a palindrome (5920238320295).
The spelling of 2510034020143 in words is "two trillion, five hundred ten billion, thirty-four million, twenty thousand, one hundred forty-three".
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