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251114585411197 is a prime number
BaseRepresentation
bin111001000110001100101011…
…101010010100111001111101
31012221010022122012212202012201
4321012030223222110321331
5230403230132331124242
62250024240432231501
7103615300343520124
oct7106145352247175
91187108565782181
10251114585411197
1173016108a14772
12241b783269b591
13aa17008457441
144602021838abb
151e070eedbd4b7
hexe4632ba94e7d

251114585411197 has 2 divisors, whose sum is σ = 251114585411198. Its totient is φ = 251114585411196.

The previous prime is 251114585411113. The next prime is 251114585411273. The reversal of 251114585411197 is 791114585411152.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 165944223580356 + 85170361830841 = 12881934^2 + 9228779^2 .

It is a cyclic number.

It is not a de Polignac number, because 251114585411197 - 227 = 251114451193469 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (251114585411597) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 125557292705598 + 125557292705599.

It is an arithmetic number, because the mean of its divisors is an integer number (125557292705599).

Almost surely, 2251114585411197 is an apocalyptic number.

It is an amenable number.

251114585411197 is a deficient number, since it is larger than the sum of its proper divisors (1).

251114585411197 is an equidigital number, since it uses as much as digits as its factorization.

251114585411197 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2016000, while the sum is 55.

The spelling of 251114585411197 in words is "two hundred fifty-one trillion, one hundred fourteen billion, five hundred eighty-five million, four hundred eleven thousand, one hundred ninety-seven".