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25121153117 is a prime number
BaseRepresentation
bin10111011001010101…
…100110000001011101
32101211201212210122102
4113121111212001131
5402422003344432
615312425254445
71546345164314
oct273125460135
971751783572
1025121153117
11a721266175
124a51034425
1324a4675258
1413044c327b
159c0654962
hex5d956605d

25121153117 has 2 divisors, whose sum is σ = 25121153118. Its totient is φ = 25121153116.

The previous prime is 25121153039. The next prime is 25121153137. The reversal of 25121153117 is 71135112152.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 15994407961 + 9126745156 = 126469^2 + 95534^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-25121153117 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 25121153117.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (25121153137) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12560576558 + 12560576559.

It is an arithmetic number, because the mean of its divisors is an integer number (12560576559).

Almost surely, 225121153117 is an apocalyptic number.

It is an amenable number.

25121153117 is a deficient number, since it is larger than the sum of its proper divisors (1).

25121153117 is an equidigital number, since it uses as much as digits as its factorization.

25121153117 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2100, while the sum is 29.

Adding to 25121153117 its reverse (71135112152), we get a palindrome (96256265269).

The spelling of 25121153117 in words is "twenty-five billion, one hundred twenty-one million, one hundred fifty-three thousand, one hundred seventeen".