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2512388862017 is a prime number
BaseRepresentation
bin100100100011110110000…
…010111011000001000001
322220011220200212221221222
4210203312002323001001
5312130333022041032
65202101524324425
7346341223653566
oct44436602730101
98804820787858
102512388862017
11889553018721
12346b01b43715
13152bc0288718
14898591d686d
1545546594a12
hex248f60bb041

2512388862017 has 2 divisors, whose sum is σ = 2512388862018. Its totient is φ = 2512388862016.

The previous prime is 2512388861987. The next prime is 2512388862029. The reversal of 2512388862017 is 7102688832152.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2501360501761 + 11028360256 = 1581569^2 + 105016^2 .

It is a cyclic number.

It is not a de Polignac number, because 2512388862017 - 28 = 2512388861761 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 2512388862017.

It is not a weakly prime, because it can be changed into another prime (2512388802017) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1256194431008 + 1256194431009.

It is an arithmetic number, because the mean of its divisors is an integer number (1256194431009).

Almost surely, 22512388862017 is an apocalyptic number.

It is an amenable number.

2512388862017 is a deficient number, since it is larger than the sum of its proper divisors (1).

2512388862017 is an equidigital number, since it uses as much as digits as its factorization.

2512388862017 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2580480, while the sum is 53.

The spelling of 2512388862017 in words is "two trillion, five hundred twelve billion, three hundred eighty-eight million, eight hundred sixty-two thousand, seventeen".