Base | Representation |
---|---|
bin | 1011011011001111100010… |
… | …01111010010110101000011 |
3 | 10021221221211010101122201002 |
4 | 11231213301033102311003 |
5 | 11243123114111021033 |
6 | 125234224125002215 |
7 | 5202146426003453 |
oct | 555476117226503 |
9 | 107857733348632 |
10 | 25125311032643 |
11 | 8007648076098 |
12 | 29995539b336b |
13 | 11033ca982613 |
14 | 62c100453d63 |
15 | 2d88789523e8 |
hex | 16d9f13d2d43 |
25125311032643 has 2 divisors, whose sum is σ = 25125311032644. Its totient is φ = 25125311032642.
The previous prime is 25125311032631. The next prime is 25125311032673. The reversal of 25125311032643 is 34623011352152.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 25125311032643 - 28 = 25125311032387 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 25125311032597 and 25125311032606.
It is not a weakly prime, because it can be changed into another prime (25125311032673) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12562655516321 + 12562655516322.
It is an arithmetic number, because the mean of its divisors is an integer number (12562655516322).
Almost surely, 225125311032643 is an apocalyptic number.
25125311032643 is a deficient number, since it is larger than the sum of its proper divisors (1).
25125311032643 is an equidigital number, since it uses as much as digits as its factorization.
25125311032643 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 129600, while the sum is 38.
Adding to 25125311032643 its reverse (34623011352152), we get a palindrome (59748322384795).
The spelling of 25125311032643 in words is "twenty-five trillion, one hundred twenty-five billion, three hundred eleven million, thirty-two thousand, six hundred forty-three".
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