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2512990793 is a prime number
BaseRepresentation
bin1001010111001001…
…0011001001001001
320111010122011022002
42111302103021021
520121311201133
61053210040345
7116163032525
oct22562231111
96433564262
102512990793
11107a5771a5
125a17190b5
1331082a401
1419ba72d85
15ea944ce8
hex95c93249

2512990793 has 2 divisors, whose sum is σ = 2512990794. Its totient is φ = 2512990792.

The previous prime is 2512990759. The next prime is 2512990817. The reversal of 2512990793 is 3970992152.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1776791104 + 736199689 = 42152^2 + 27133^2 .

It is a cyclic number.

It is not a de Polignac number, because 2512990793 - 26 = 2512990729 is a prime.

It is not a weakly prime, because it can be changed into another prime (2512990703) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1256495396 + 1256495397.

It is an arithmetic number, because the mean of its divisors is an integer number (1256495397).

Almost surely, 22512990793 is an apocalyptic number.

It is an amenable number.

2512990793 is a deficient number, since it is larger than the sum of its proper divisors (1).

2512990793 is an equidigital number, since it uses as much as digits as its factorization.

2512990793 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 306180, while the sum is 47.

The square root of 2512990793 is about 50129.7396063455. The cubic root of 2512990793 is about 1359.5555772853. Note that the first 4 decimals are identical.

The spelling of 2512990793 in words is "two billion, five hundred twelve million, nine hundred ninety thousand, seven hundred ninety-three".