2513000011 has 2 divisors, whose sum is σ = 2513000012. Its totient is φ = 2513000010.

The previous prime is 2512999997. The next prime is 2513000041. The reversal of 2513000011 is 1100003152.

2513000011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 2513000011 - 2¹⁹ = 2512475723 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2512999955 and 2513000000.

It is not a weakly prime, because it can be changed into another prime (2513000041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1256500005 + 1256500006.

It is an arithmetic number, because the mean of its divisors is an integer number (1256500006).

Almost surely, 2^2513000011 is an apocalyptic number.

2513000011 is a deficient number, since it is larger than the sum of its proper divisors (1).

2513000011 is an equidigital number, since it uses as much as digits as its factorization.

2513000011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 30, while the sum is 13.

The square root of 2513000011 is about 50129.8315476922. The cubic root of 2513000011 is about 1359.5572396296.

Adding to 2513000011 its reverse (1100003152), we get a palindrome (3613003163).

The spelling of 2513000011 in words is "two billion, five hundred thirteen million, eleven", and thus it is an aban number.