Base | Representation |
---|---|
bin | 100100100100011010110… |
… | …001011101111010001110 |
3 | 22220020111122100012211112 |
4 | 210210122301131322032 |
5 | 312133113242341332 |
6 | 5202243015252022 |
7 | 346362415265603 |
oct | 44443261357216 |
9 | 8806448305745 |
10 | 2513005043342 |
11 | 889839918892 |
12 | 34705437a012 |
13 | 152c8ab2b561 |
14 | 898b6d926aa |
15 | 4558070bdb2 |
hex | 2491ac5de8e |
2513005043342 has 4 divisors (see below), whose sum is σ = 3769507565016. Its totient is φ = 1256502521670.
The previous prime is 2513005043261. The next prime is 2513005043407. The reversal of 2513005043342 is 2433405003152.
2513005043342 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a junction number, because it is equal to n+sod(n) for n = 2513005043299 and 2513005043308.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 628251260834 + ... + 628251260837.
It is an arithmetic number, because the mean of its divisors is an integer number (942376891254).
Almost surely, 22513005043342 is an apocalyptic number.
2513005043342 is a deficient number, since it is larger than the sum of its proper divisors (1256502521674).
2513005043342 is a wasteful number, since it uses less digits than its factorization.
2513005043342 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1256502521673.
The product of its (nonzero) digits is 43200, while the sum is 32.
The spelling of 2513005043342 in words is "two trillion, five hundred thirteen billion, five million, forty-three thousand, three hundred forty-two".
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