Base | Representation |
---|---|
bin | 1011011011011010001011… |
… | …00101100001111110110001 |
3 | 10021222111120001220220120102 |
4 | 11231231011211201332301 |
5 | 11243221312401142223 |
6 | 125241010503522145 |
7 | 5202441062625011 |
oct | 555550545417661 |
9 | 107874501826512 |
10 | 25131021115313 |
11 | 800a008289783 |
12 | 299a688159355 |
13 | 1103aca970969 |
14 | 62c4c2955c41 |
15 | 2d8aaedbd928 |
hex | 16db45961fb1 |
25131021115313 has 2 divisors, whose sum is σ = 25131021115314. Its totient is φ = 25131021115312.
The previous prime is 25131021115309. The next prime is 25131021115349. The reversal of 25131021115313 is 31351112013152.
It is a happy number.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 25083790090384 + 47231024929 = 5008372^2 + 217327^2 .
It is a cyclic number.
It is not a de Polignac number, because 25131021115313 - 22 = 25131021115309 is a prime.
It is not a weakly prime, because it can be changed into another prime (25131021115513) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12565510557656 + 12565510557657.
It is an arithmetic number, because the mean of its divisors is an integer number (12565510557657).
Almost surely, 225131021115313 is an apocalyptic number.
It is an amenable number.
25131021115313 is a deficient number, since it is larger than the sum of its proper divisors (1).
25131021115313 is an equidigital number, since it uses as much as digits as its factorization.
25131021115313 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2700, while the sum is 29.
Adding to 25131021115313 its reverse (31351112013152), we get a palindrome (56482133128465).
The spelling of 25131021115313 in words is "twenty-five trillion, one hundred thirty-one billion, twenty-one million, one hundred fifteen thousand, three hundred thirteen".
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