2513102413483 has 2 divisors, whose sum is σ = 2513102413484. Its totient is φ = 2513102413482.

The previous prime is 2513102413447. The next prime is 2513102413519. The reversal of 2513102413483 is 3843142013152.

It is a balanced prime because it is at equal distance from previous prime (2513102413447) and next prime (2513102413519).

It is a cyclic number.

It is not a de Polignac number, because 2513102413483 - 2¹³ = 2513102405291 is a prime.

It is a super-4 number, since 4×2513102413483⁴ (a number of 51 digits) contains 4444 as substring.

It is not a weakly prime, because it can be changed into another prime (2513102413403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1256551206741 + 1256551206742.

It is an arithmetic number, because the mean of its divisors is an integer number (1256551206742).

Almost surely, 2^{2513102413483} is an apocalyptic number.

2513102413483 is a deficient number, since it is larger than the sum of its proper divisors (1).

2513102413483 is an equidigital number, since it uses as much as digits as its factorization.

2513102413483 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 69120, while the sum is 37.

The spelling of 2513102413483 in words is "two trillion, five hundred thirteen billion, one hundred two million, four hundred thirteen thousand, four hundred eighty-three".