Base | Representation |
---|---|
bin | 100100100100111000010… |
… | …010010111000110000001 |
3 | 22220021210011002001112112 |
4 | 210210320102113012001 |
5 | 312140122023033231 |
6 | 5202404104305105 |
7 | 346410610143101 |
oct | 44447022270601 |
9 | 8807704061475 |
10 | 2513500205441 |
11 | 889a73380465 |
12 | 347172172195 |
13 | 1530395ab594 |
14 | 89922a49201 |
15 | 455ade1b92b |
hex | 24938497181 |
2513500205441 has 2 divisors, whose sum is σ = 2513500205442. Its totient is φ = 2513500205440.
The previous prime is 2513500205401. The next prime is 2513500205497. The reversal of 2513500205441 is 1445020053152.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2503027753216 + 10472452225 = 1582096^2 + 102335^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-2513500205441 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2513500205398 and 2513500205407.
It is not a weakly prime, because it can be changed into another prime (2513500205401) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1256750102720 + 1256750102721.
It is an arithmetic number, because the mean of its divisors is an integer number (1256750102721).
Almost surely, 22513500205441 is an apocalyptic number.
It is an amenable number.
2513500205441 is a deficient number, since it is larger than the sum of its proper divisors (1).
2513500205441 is an equidigital number, since it uses as much as digits as its factorization.
2513500205441 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24000, while the sum is 32.
Adding to 2513500205441 its reverse (1445020053152), we get a palindrome (3958520258593).
The spelling of 2513500205441 in words is "two trillion, five hundred thirteen billion, five hundred million, two hundred five thousand, four hundred forty-one".
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