Base | Representation |
---|---|
bin | 10111011010001010… |
… | …011011011100100001 |
3 | 2101212200221110200210 |
4 | 113122022123130201 |
5 | 402434030102200 |
6 | 15314042204333 |
7 | 1546604001240 |
oct | 273212333441 |
9 | 71780843623 |
10 | 25135003425 |
11 | a729066104 |
12 | 4a557b36a9 |
13 | 24a74b44bc |
14 | 130628a957 |
15 | 9c198d650 |
hex | 5da29b721 |
25135003425 has 96 divisors (see below), whose sum is σ = 47966929920. Its totient is φ = 11376288000.
The previous prime is 25135003417. The next prime is 25135003427. The reversal of 25135003425 is 52430053152.
It is not a de Polignac number, because 25135003425 - 23 = 25135003417 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 25135003392 and 25135003401.
It is not an unprimeable number, because it can be changed into a prime (25135003427) by changing a digit.
It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 35855575 + ... + 35856275.
It is an arithmetic number, because the mean of its divisors is an integer number (499655520).
Almost surely, 225135003425 is an apocalyptic number.
25135003425 is a gapful number since it is divisible by the number (25) formed by its first and last digit.
It is an amenable number.
25135003425 is a deficient number, since it is larger than the sum of its proper divisors (22831926495).
25135003425 is a wasteful number, since it uses less digits than its factorization.
25135003425 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1303 (or 1298 counting only the distinct ones).
The product of its (nonzero) digits is 18000, while the sum is 30.
Adding to 25135003425 its reverse (52430053152), we get a palindrome (77565056577).
The spelling of 25135003425 in words is "twenty-five billion, one hundred thirty-five million, three thousand, four hundred twenty-five".
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