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2513715401 is a prime number
BaseRepresentation
bin1001010111010100…
…0100000011001001
320111011222222021102
42111311010003021
520122002343101
61053233351145
7116202141221
oct22565040311
96434888242
102513715401
11107aa2164a
125a1a084b5
13310a22182
1419bbc1081
15eaa3986b
hex95d440c9

2513715401 has 2 divisors, whose sum is σ = 2513715402. Its totient is φ = 2513715400.

The previous prime is 2513715349. The next prime is 2513715403. The reversal of 2513715401 is 1045173152.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2418672400 + 95043001 = 49180^2 + 9749^2 .

It is a cyclic number.

It is not a de Polignac number, because 2513715401 - 214 = 2513699017 is a prime.

Together with 2513715403, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (2513715403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1256857700 + 1256857701.

It is an arithmetic number, because the mean of its divisors is an integer number (1256857701).

Almost surely, 22513715401 is an apocalyptic number.

It is an amenable number.

2513715401 is a deficient number, since it is larger than the sum of its proper divisors (1).

2513715401 is an equidigital number, since it uses as much as digits as its factorization.

2513715401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4200, while the sum is 29.

The square root of 2513715401 is about 50136.9664120198. The cubic root of 2513715401 is about 1359.6862383524.

Adding to 2513715401 its reverse (1045173152), we get a palindrome (3558888553).

The spelling of 2513715401 in words is "two billion, five hundred thirteen million, seven hundred fifteen thousand, four hundred one".