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2513777640113 is a prime number
BaseRepresentation
bin100100100101001000110…
…100101100001010110001
322220022111111010012100202
4210211020310230022301
5312141204033440423
65202451414524545
7346420516250405
oct44451064541261
98808444105322
102513777640113
1188a0a5a42213
1234722b066755
13153081c083cc
148994b827105
15455c846e728
hex24948d2c2b1

2513777640113 has 2 divisors, whose sum is σ = 2513777640114. Its totient is φ = 2513777640112.

The previous prime is 2513777640097. The next prime is 2513777640131. The reversal of 2513777640113 is 3110467773152.

Together with next prime (2513777640131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2424037252624 + 89740387489 = 1556932^2 + 299567^2 .

It is a cyclic number.

It is not a de Polignac number, because 2513777640113 - 24 = 2513777640097 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (2513773640113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1256888820056 + 1256888820057.

It is an arithmetic number, because the mean of its divisors is an integer number (1256888820057).

Almost surely, 22513777640113 is an apocalyptic number.

It is an amenable number.

2513777640113 is a deficient number, since it is larger than the sum of its proper divisors (1).

2513777640113 is an equidigital number, since it uses as much as digits as its factorization.

2513777640113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 740880, while the sum is 47.

The spelling of 2513777640113 in words is "two trillion, five hundred thirteen billion, seven hundred seventy-seven million, six hundred forty thousand, one hundred thirteen".