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2514012013 is a prime number
BaseRepresentation
bin1001010111011000…
…1100011101101101
320111012120001011001
42111312030131231
520122041341023
61053244000301
7116204515042
oct22566143555
96435501131
102514012013
111080104487
125a1b30091
13310ac7196
1419bc5b1c9
15eaa976ad
hex95d8c76d

2514012013 has 2 divisors, whose sum is σ = 2514012014. Its totient is φ = 2514012012.

The previous prime is 2514011993. The next prime is 2514012019. The reversal of 2514012013 is 3102104152.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2030583844 + 483428169 = 45062^2 + 21987^2 .

It is a cyclic number.

It is not a de Polignac number, because 2514012013 - 29 = 2514011501 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (2514012019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1257006006 + 1257006007.

It is an arithmetic number, because the mean of its divisors is an integer number (1257006007).

Almost surely, 22514012013 is an apocalyptic number.

It is an amenable number.

2514012013 is a deficient number, since it is larger than the sum of its proper divisors (1).

2514012013 is an equidigital number, since it uses as much as digits as its factorization.

2514012013 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 240, while the sum is 19.

The square root of 2514012013 is about 50139.9243417858. The cubic root of 2514012013 is about 1359.7397160840.

Adding to 2514012013 its reverse (3102104152), we get a palindrome (5616116165).

The spelling of 2514012013 in words is "two billion, five hundred fourteen million, twelve thousand, thirteen".