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2514340434139 is a prime number
BaseRepresentation
bin100100100101101010010…
…111100101000011011011
322220100221201010002121221
4210211222113211003123
5312143332122343024
65203023321312511
7346440462026332
oct44455227450333
98810851102557
102514340434139
1188a364698746
12347367635737
131531416a8121
14899a2486d19
154560ca8d3e4
hex2496a5e50db

2514340434139 has 2 divisors, whose sum is σ = 2514340434140. Its totient is φ = 2514340434138.

The previous prime is 2514340434127. The next prime is 2514340434173. The reversal of 2514340434139 is 9314340434152.

It is a happy number.

2514340434139 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 2514340434139 - 221 = 2514338336987 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2514340434095 and 2514340434104.

It is not a weakly prime, because it can be changed into another prime (2514340434119) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1257170217069 + 1257170217070.

It is an arithmetic number, because the mean of its divisors is an integer number (1257170217070).

Almost surely, 22514340434139 is an apocalyptic number.

2514340434139 is a deficient number, since it is larger than the sum of its proper divisors (1).

2514340434139 is an equidigital number, since it uses as much as digits as its factorization.

2514340434139 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 622080, while the sum is 43.

The spelling of 2514340434139 in words is "two trillion, five hundred fourteen billion, three hundred forty million, four hundred thirty-four thousand, one hundred thirty-nine".