Base | Representation |
---|---|
bin | 1011011100001011100010… |
… | …01110111100110101111111 |
3 | 10022002000222001021011111221 |
4 | 11232011301032330311333 |
5 | 11244140101414303221 |
6 | 125301112343254211 |
7 | 5204366606615131 |
oct | 556056116746577 |
9 | 108060861234457 |
10 | 25157523197311 |
11 | 801a277a9818a |
12 | 29a384374a367 |
13 | 1106462447c9b |
14 | 62d8b85c5051 |
15 | 2d961189c541 |
hex | 16e1713bcd7f |
25157523197311 has 2 divisors, whose sum is σ = 25157523197312. Its totient is φ = 25157523197310.
The previous prime is 25157523197243. The next prime is 25157523197353. The reversal of 25157523197311 is 11379132575152.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-25157523197311 is a prime.
It is a super-4 number, since 4×251575231973114 (a number of 55 digits) contains 4444 as substring. Note that it is a super-d number also for d = 3.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (25157523197381) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12578761598655 + 12578761598656.
It is an arithmetic number, because the mean of its divisors is an integer number (12578761598656).
Almost surely, 225157523197311 is an apocalyptic number.
25157523197311 is a deficient number, since it is larger than the sum of its proper divisors (1).
25157523197311 is an equidigital number, since it uses as much as digits as its factorization.
25157523197311 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1984500, while the sum is 52.
The spelling of 25157523197311 in words is "twenty-five trillion, one hundred fifty-seven billion, five hundred twenty-three million, one hundred ninety-seven thousand, three hundred eleven".
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