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25160314345141 is a prime number
BaseRepresentation
bin1011011100010000101111…
…00110010101011010110101
310022002022011120022011112111
411232020113212111122311
511244211310433021031
6125302253331251021
75204526021154303
oct556102746253265
9108068146264474
1025160314345141
11802047a579928
1229a42a2449a71
1311067b8795c51
1462daa1183273
152d97269391b1
hex16e2179956b5

25160314345141 has 2 divisors, whose sum is σ = 25160314345142. Its totient is φ = 25160314345140.

The previous prime is 25160314345123. The next prime is 25160314345237. The reversal of 25160314345141 is 14154341306152.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 24404301485041 + 756012860100 = 4940071^2 + 869490^2 .

It is a cyclic number.

It is not a de Polignac number, because 25160314345141 - 229 = 25159777474229 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 25160314345094 and 25160314345103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (25160314345541) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12580157172570 + 12580157172571.

It is an arithmetic number, because the mean of its divisors is an integer number (12580157172571).

Almost surely, 225160314345141 is an apocalyptic number.

It is an amenable number.

25160314345141 is a deficient number, since it is larger than the sum of its proper divisors (1).

25160314345141 is an equidigital number, since it uses as much as digits as its factorization.

25160314345141 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 172800, while the sum is 40.

The spelling of 25160314345141 in words is "twenty-five trillion, one hundred sixty billion, three hundred fourteen million, three hundred forty-five thousand, one hundred forty-one".