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25171253322847 is a prime number
BaseRepresentation
bin1011011100100101000111…
…00111001110010001011111
310022010100101220220210220221
411232102203213032101133
511244401211322312342
6125311303015422211
75205364060014502
oct556224347162137
9108110356823827
1025171253322847
118025083318775
1229a6435984967
13110783cb76218
1463041bccb139
152d9b66e72a67
hex16e4a39ce45f

25171253322847 has 2 divisors, whose sum is σ = 25171253322848. Its totient is φ = 25171253322846.

The previous prime is 25171253322841. The next prime is 25171253322869. The reversal of 25171253322847 is 74822335217152.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 25171253322847 - 223 = 25171244934239 is a prime.

It is a super-2 number, since 2×251712533228472 (a number of 28 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 25171253322794 and 25171253322803.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (25171253322841) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12585626661423 + 12585626661424.

It is an arithmetic number, because the mean of its divisors is an integer number (12585626661424).

Almost surely, 225171253322847 is an apocalyptic number.

25171253322847 is a deficient number, since it is larger than the sum of its proper divisors (1).

25171253322847 is an equidigital number, since it uses as much as digits as its factorization.

25171253322847 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 5644800, while the sum is 52.

Adding to 25171253322847 its reverse (74822335217152), we get a palindrome (99993588539999).

The spelling of 25171253322847 in words is "twenty-five trillion, one hundred seventy-one billion, two hundred fifty-three million, three hundred twenty-two thousand, eight hundred forty-seven".