Search a number
-
+
251714497 is a prime number
BaseRepresentation
bin11110000000011…
…01101111000001
3122112122102101011
433000031233001
51003414330442
640551040521
76144352336
oct1700155701
9575572334
10251714497
1111a0a4911
1270370141
13401c2bb8
142560498d
1517172117
hexf00dbc1

251714497 has 2 divisors, whose sum is σ = 251714498. Its totient is φ = 251714496.

The previous prime is 251714479. The next prime is 251714537. The reversal of 251714497 is 794417152.

Together with previous prime (251714479) it forms an Ormiston pair, because they use the same digits, order apart.

It is an a-pointer prime, because the next prime (251714537) can be obtained adding 251714497 to its sum of digits (40).

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 220700736 + 31013761 = 14856^2 + 5569^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-251714497 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (251714417) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 125857248 + 125857249.

It is an arithmetic number, because the mean of its divisors is an integer number (125857249).

Almost surely, 2251714497 is an apocalyptic number.

It is an amenable number.

251714497 is a deficient number, since it is larger than the sum of its proper divisors (1).

251714497 is an equidigital number, since it uses as much as digits as its factorization.

251714497 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 70560, while the sum is 40.

The square root of 251714497 is about 15865.5128186895. The cubic root of 251714497 is about 631.3973326395.

The spelling of 251714497 in words is "two hundred fifty-one million, seven hundred fourteen thousand, four hundred ninety-seven".