Base | Representation |
---|---|
bin | 10111011110000011… |
… | …010101010011010011 |
3 | 2102001020201110001221 |
4 | 113132003111103103 |
5 | 403102231031430 |
6 | 15324332505511 |
7 | 1551325415533 |
oct | 273603252323 |
9 | 72036643057 |
10 | 25200252115 |
11 | a761981445 |
12 | 4a7361b297 |
13 | 24b7b7b4ac |
14 | 1310bd34c3 |
15 | 9c757b57a |
hex | 5de0d54d3 |
25200252115 has 32 divisors (see below), whose sum is σ = 31691088000. Its totient is φ = 19216364544.
The previous prime is 25200252113. The next prime is 25200252127. The reversal of 25200252115 is 51125200252.
It is a cyclic number.
It is not a de Polignac number, because 25200252115 - 21 = 25200252113 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 25200252115.
It is not an unprimeable number, because it can be changed into a prime (25200252113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 8401386 + ... + 8404384.
It is an arithmetic number, because the mean of its divisors is an integer number (990346500).
Almost surely, 225200252115 is an apocalyptic number.
25200252115 is a deficient number, since it is larger than the sum of its proper divisors (6490835885).
25200252115 is a wasteful number, since it uses less digits than its factorization.
25200252115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3951.
The product of its (nonzero) digits is 2000, while the sum is 25.
Adding to 25200252115 its reverse (51125200252), we get a palindrome (76325452367).
The spelling of 25200252115 in words is "twenty-five billion, two hundred million, two hundred fifty-two thousand, one hundred fifteen".
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