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25200346141111 is a prime number
BaseRepresentation
bin1011011101011011010011…
…01011100001000110110111
310022020010111110012002220111
411232231221223201012313
511300340302103003421
6125332513523443451
75210444032623601
oct556555153410667
9108203443162814
1025200346141111
118036452474729
1229abbb4b26587
13110a4c82cba9b
146319bba6a171
152da7bb101ee1
hex16eb69ae11b7

25200346141111 has 2 divisors, whose sum is σ = 25200346141112. Its totient is φ = 25200346141110.

The previous prime is 25200346141097. The next prime is 25200346141133. The reversal of 25200346141111 is 11114164300252.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-25200346141111 is a prime.

It is a super-4 number, since 4×252003461411114 (a number of 55 digits) contains 4444 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (25200346141141) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12600173070555 + 12600173070556.

It is an arithmetic number, because the mean of its divisors is an integer number (12600173070556).

Almost surely, 225200346141111 is an apocalyptic number.

25200346141111 is a deficient number, since it is larger than the sum of its proper divisors (1).

25200346141111 is an equidigital number, since it uses as much as digits as its factorization.

25200346141111 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 5760, while the sum is 31.

The spelling of 25200346141111 in words is "twenty-five trillion, two hundred billion, three hundred forty-six million, one hundred forty-one thousand, one hundred eleven".