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2520140393 is a prime number
BaseRepresentation
bin1001011000110110…
…0100101001101001
320111122002101201002
42112031210221221
520130123443033
61054023204345
7116310561041
oct22615445151
96448071632
102520140393
11108360a861
125a3ba66b5
13312161744
1419c9b4721
15eb3a83e8
hex96364a69

2520140393 has 2 divisors, whose sum is σ = 2520140394. Its totient is φ = 2520140392.

The previous prime is 2520140353. The next prime is 2520140417. The reversal of 2520140393 is 3930410252.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1436940649 + 1083199744 = 37907^2 + 32912^2 .

It is a cyclic number.

It is not a de Polignac number, because 2520140393 - 28 = 2520140137 is a prime.

It is a super-2 number, since 2×25201403932 = 12702215200860388898, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (2520140303) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1260070196 + 1260070197.

It is an arithmetic number, because the mean of its divisors is an integer number (1260070197).

Almost surely, 22520140393 is an apocalyptic number.

It is an amenable number.

2520140393 is a deficient number, since it is larger than the sum of its proper divisors (1).

2520140393 is an equidigital number, since it uses as much as digits as its factorization.

2520140393 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6480, while the sum is 29.

The square root of 2520140393 is about 50200.9999203203. Note that the first 4 decimals coincide. The cubic root of 2520140393 is about 1360.8436938035.

The spelling of 2520140393 in words is "two billion, five hundred twenty million, one hundred forty thousand, three hundred ninety-three".