Base | Representation |
---|---|
bin | 1110101011001100001… |
… | …1100011000110100111 |
3 | 220002202010111110010222 |
4 | 3222303003203012213 |
5 | 13112311202430142 |
6 | 311452502234555 |
7 | 24133400650124 |
oct | 3526303430647 |
9 | 802663443128 |
10 | 252112155047 |
11 | 97a13814635 |
12 | 40a3ba25a5b |
13 | 1aa0a84448c |
14 | c2b914374b |
15 | 6858482bd2 |
hex | 3ab30e31a7 |
252112155047 has 2 divisors, whose sum is σ = 252112155048. Its totient is φ = 252112155046.
The previous prime is 252112154993. The next prime is 252112155103. The reversal of 252112155047 is 740551211252.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-252112155047 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 252112154998 and 252112155016.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (252112155247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 126056077523 + 126056077524.
It is an arithmetic number, because the mean of its divisors is an integer number (126056077524).
Almost surely, 2252112155047 is an apocalyptic number.
252112155047 is a deficient number, since it is larger than the sum of its proper divisors (1).
252112155047 is an equidigital number, since it uses as much as digits as its factorization.
252112155047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 28000, while the sum is 35.
Adding to 252112155047 its reverse (740551211252), we get a palindrome (992663366299).
The spelling of 252112155047 in words is "two hundred fifty-two billion, one hundred twelve million, one hundred fifty-five thousand, forty-seven".
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