Base | Representation |
---|---|
bin | 111001010101000001001010… |
… | …100101101101011110100011 |
3 | 1020001201200101002022200222202 |
4 | 321111001022211231132203 |
5 | 231021421401423401341 |
6 | 2252124150110523415 |
7 | 104052003033023645 |
oct | 7125011245553643 |
9 | 1201650332280882 |
10 | 252133011543971 |
11 | 73379011a16968 |
12 | 2434109750656b |
13 | aa8c06c01480c |
14 | 4639435116895 |
15 | 1e2385911479b |
hex | e5504a96d7a3 |
252133011543971 has 2 divisors, whose sum is σ = 252133011543972. Its totient is φ = 252133011543970.
The previous prime is 252133011543967. The next prime is 252133011543979. The reversal of 252133011543971 is 179345110331252.
252133011543971 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 252133011543971 - 22 = 252133011543967 is a prime.
It is not a weakly prime, because it can be changed into another prime (252133011543979) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 126066505771985 + 126066505771986.
It is an arithmetic number, because the mean of its divisors is an integer number (126066505771986).
Almost surely, 2252133011543971 is an apocalyptic number.
252133011543971 is a deficient number, since it is larger than the sum of its proper divisors (1).
252133011543971 is an equidigital number, since it uses as much as digits as its factorization.
252133011543971 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 680400, while the sum is 47.
The spelling of 252133011543971 in words is "two hundred fifty-two trillion, one hundred thirty-three billion, eleven million, five hundred forty-three thousand, nine hundred seventy-one".
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