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252140888249 is a prime number
BaseRepresentation
bin1110101011010011000…
…1001010000010111001
3220002211010120020200122
43222310301022002321
513112341031410444
6311455410143025
724134200121315
oct3526461120271
9802733506618
10252140888249
1197a28a5a288
1240a49581a75
131aa13794983
14c2bcca2b45
15685ac5b4ee
hex3ab4c4a0b9

252140888249 has 2 divisors, whose sum is σ = 252140888250. Its totient is φ = 252140888248.

The previous prime is 252140888183. The next prime is 252140888261. The reversal of 252140888249 is 942888041252.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 224529084025 + 27611804224 = 473845^2 + 166168^2 .

It is a cyclic number.

It is not a de Polignac number, because 252140888249 - 220 = 252139839673 is a prime.

It is a super-3 number, since 3×2521408882493 (a number of 35 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 252140888249.

It is not a weakly prime, because it can be changed into another prime (252140818249) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 126070444124 + 126070444125.

It is an arithmetic number, because the mean of its divisors is an integer number (126070444125).

Almost surely, 2252140888249 is an apocalyptic number.

It is an amenable number.

252140888249 is a deficient number, since it is larger than the sum of its proper divisors (1).

252140888249 is an equidigital number, since it uses as much as digits as its factorization.

252140888249 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2949120, while the sum is 53.

The spelling of 252140888249 in words is "two hundred fifty-two billion, one hundred forty million, eight hundred eighty-eight thousand, two hundred forty-nine".