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252224501393 is a prime number
BaseRepresentation
bin1110101011100111000…
…0000111011010010001
3220010000221220020100202
43222321300013122101
513113023433021033
6311511554224545
724136233613364
oct3527160073221
9803027806322
10252224501393
1197a71179057
1240a71585155
131aa27bbb7c7
14c2ca02a0db
1568632758e8
hex3ab9c07691

252224501393 has 2 divisors, whose sum is σ = 252224501394. Its totient is φ = 252224501392.

The previous prime is 252224501323. The next prime is 252224501407. The reversal of 252224501393 is 393105422252.

252224501393 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 241339335169 + 10885166224 = 491263^2 + 104332^2 .

It is a cyclic number.

It is not a de Polignac number, because 252224501393 - 218 = 252224239249 is a prime.

It is not a weakly prime, because it can be changed into another prime (252224501303) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 126112250696 + 126112250697.

It is an arithmetic number, because the mean of its divisors is an integer number (126112250697).

Almost surely, 2252224501393 is an apocalyptic number.

It is an amenable number.

252224501393 is a deficient number, since it is larger than the sum of its proper divisors (1).

252224501393 is an equidigital number, since it uses as much as digits as its factorization.

252224501393 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 129600, while the sum is 38.

The spelling of 252224501393 in words is "two hundred fifty-two billion, two hundred twenty-four million, five hundred one thousand, three hundred ninety-three".