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252441331 is a prime number
BaseRepresentation
bin11110000101111…
…11001011110011
3122121000100101221
433002333023303
51004111110311
641014405511
76153500362
oct1702771363
9577010357
10252441331
1111a5509aa
1270660897
13403b898c
14257537d9
1517267671
hexf0bf2f3

252441331 has 2 divisors, whose sum is σ = 252441332. Its totient is φ = 252441330.

The previous prime is 252441289. The next prime is 252441341. The reversal of 252441331 is 133144252.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 252441331 - 217 = 252310259 is a prime.

It is a super-2 number, since 2×2524413312 = 127453251194103122, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 252441296 and 252441305.

It is not a weakly prime, because it can be changed into another prime (252441341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 126220665 + 126220666.

It is an arithmetic number, because the mean of its divisors is an integer number (126220666).

Almost surely, 2252441331 is an apocalyptic number.

252441331 is a deficient number, since it is larger than the sum of its proper divisors (1).

252441331 is an equidigital number, since it uses as much as digits as its factorization.

252441331 is an evil number, because the sum of its binary digits is even.

The product of its digits is 2880, while the sum is 25.

The square root of 252441331 is about 15888.4024055284. The cubic root of 252441331 is about 632.0044755799.

Adding to 252441331 its reverse (133144252), we get a palindrome (385585583).

The spelling of 252441331 in words is "two hundred fifty-two million, four hundred forty-one thousand, three hundred thirty-one".