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25244913120107 is a prime number
BaseRepresentation
bin1011011110101110010100…
…00101000011001101101011
310022101101112101211012211012
411233113022011003031223
511302103040224320412
6125405204124454135
75213612323660142
oct557271205031553
9108341471735735
1025244913120107
11805334236067a
1229b87723aa34b
13111177b5a9585
14633c089ba759
152dba28a07c22
hex16f5ca14336b

25244913120107 has 2 divisors, whose sum is σ = 25244913120108. Its totient is φ = 25244913120106.

The previous prime is 25244913120071. The next prime is 25244913120143. The reversal of 25244913120107 is 70102131944252.

Together with previous prime (25244913120071) it forms an Ormiston pair, because they use the same digits, order apart.

It is a balanced prime because it is at equal distance from previous prime (25244913120071) and next prime (25244913120143).

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-25244913120107 is a prime.

It is not a weakly prime, because it can be changed into another prime (25244913120197) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12622456560053 + 12622456560054.

It is an arithmetic number, because the mean of its divisors is an integer number (12622456560054).

Almost surely, 225244913120107 is an apocalyptic number.

25244913120107 is a deficient number, since it is larger than the sum of its proper divisors (1).

25244913120107 is an equidigital number, since it uses as much as digits as its factorization.

25244913120107 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 120960, while the sum is 41.

The spelling of 25244913120107 in words is "twenty-five trillion, two hundred forty-four billion, nine hundred thirteen million, one hundred twenty thousand, one hundred seven".