Base | Representation |
---|---|
bin | 100100101111100101101… |
… | …111100011110000110111 |
3 | 22221101110121102222100022 |
4 | 210233211233203300313 |
5 | 312332200031034341 |
6 | 5211545154235355 |
7 | 350265601010024 |
oct | 44574557436067 |
9 | 8841417388308 |
10 | 2525000252471 |
11 | 8939348a7a64 |
12 | 349441585b5b |
13 | 15414cca6538 |
14 | 8a2d40c454b |
15 | 45a33832e4b |
hex | 24be5be3c37 |
2525000252471 has 2 divisors, whose sum is σ = 2525000252472. Its totient is φ = 2525000252470.
The previous prime is 2525000252461. The next prime is 2525000252501. The reversal of 2525000252471 is 1742520005252.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2525000252471 - 234 = 2507820383287 is a prime.
It is a super-3 number, since 3×25250002524713 (a number of 38 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2525000252461) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1262500126235 + 1262500126236.
It is an arithmetic number, because the mean of its divisors is an integer number (1262500126236).
Almost surely, 22525000252471 is an apocalyptic number.
2525000252471 is a deficient number, since it is larger than the sum of its proper divisors (1).
2525000252471 is an equidigital number, since it uses as much as digits as its factorization.
2525000252471 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 56000, while the sum is 35.
The spelling of 2525000252471 in words is "two trillion, five hundred twenty-five billion, two hundred fifty-two thousand, four hundred seventy-one".
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