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25253027555053 is a prime number
BaseRepresentation
bin1011011110111101011011…
…01111001010011011101101
310022102011110220120012221211
411233132231233022123231
511302221200023230203
6125413025233154421
75214320364352654
oct557365557123355
9108364426505854
1025253027555053
118056826789761
1229ba2579bba11
13111247274857c
1463437855219b
152dbd510a9c6d
hex16f7adbca6ed

25253027555053 has 2 divisors, whose sum is σ = 25253027555054. Its totient is φ = 25253027555052.

The previous prime is 25253027555017. The next prime is 25253027555059. The reversal of 25253027555053 is 35055572035252.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 20505845042244 + 4747182512809 = 4528338^2 + 2178803^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-25253027555053 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 25253027554988 and 25253027555006.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (25253027555059) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12626513777526 + 12626513777527.

It is an arithmetic number, because the mean of its divisors is an integer number (12626513777527).

Almost surely, 225253027555053 is an apocalyptic number.

It is an amenable number.

25253027555053 is a deficient number, since it is larger than the sum of its proper divisors (1).

25253027555053 is an equidigital number, since it uses as much as digits as its factorization.

25253027555053 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 7875000, while the sum is 49.

The spelling of 25253027555053 in words is "twenty-five trillion, two hundred fifty-three billion, twenty-seven million, five hundred fifty-five thousand, fifty-three".