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25264748620997 is a prime number
BaseRepresentation
bin1011011111010011010000…
…10111011110110011000101
310022110021201202211001201022
411233221220113132303011
511302414201121332442
6125422244300240525
75215214010645614
oct557515027366305
9108407652731638
1025264748620997
1180607a0a45016
122a00589240145
1311135bcb79952
14634b6b0c187b
152dc2da0cd3d2
hex16fa685decc5

25264748620997 has 2 divisors, whose sum is σ = 25264748620998. Its totient is φ = 25264748620996.

The previous prime is 25264748620873. The next prime is 25264748621069. The reversal of 25264748620997 is 79902684746252.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 24557188381441 + 707560239556 = 4955521^2 + 841166^2 .

It is a cyclic number.

It is not a de Polignac number, because 25264748620997 - 228 = 25264480185541 is a prime.

It is a super-3 number, since 3×252647486209973 (a number of 41 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 25264748620997.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (25264748620297) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12632374310498 + 12632374310499.

It is an arithmetic number, because the mean of its divisors is an integer number (12632374310499).

Almost surely, 225264748620997 is an apocalyptic number.

It is an amenable number.

25264748620997 is a deficient number, since it is larger than the sum of its proper divisors (1).

25264748620997 is an equidigital number, since it uses as much as digits as its factorization.

25264748620997 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 731566080, while the sum is 71.

The spelling of 25264748620997 in words is "twenty-five trillion, two hundred sixty-four billion, seven hundred forty-eight million, six hundred twenty thousand, nine hundred ninety-seven".