Base | Representation |
---|---|
bin | 100100110010011101010… |
… | …000100010110110110111 |
3 | 22221200102011220011100211 |
4 | 210302131100202312313 |
5 | 312410001224130124 |
6 | 5213214501250251 |
7 | 350435105022331 |
oct | 44623520426667 |
9 | 8850364804324 |
10 | 2528079130039 |
11 | 895174842281 |
12 | 349b60703987 |
13 | 154520b17298 |
14 | 8a506d80451 |
15 | 45b63ca7e94 |
hex | 24c9d422db7 |
2528079130039 has 2 divisors, whose sum is σ = 2528079130040. Its totient is φ = 2528079130038.
The previous prime is 2528079130021. The next prime is 2528079130103. The reversal of 2528079130039 is 9300319708252.
2528079130039 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2528079130039 - 213 = 2528079121847 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 2528079129974 and 2528079130001.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (2528079130639) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1264039565019 + 1264039565020.
It is an arithmetic number, because the mean of its divisors is an integer number (1264039565020).
Almost surely, 22528079130039 is an apocalyptic number.
2528079130039 is a deficient number, since it is larger than the sum of its proper divisors (1).
2528079130039 is an equidigital number, since it uses as much as digits as its factorization.
2528079130039 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 816480, while the sum is 49.
The spelling of 2528079130039 in words is "two trillion, five hundred twenty-eight billion, seventy-nine million, one hundred thirty thousand, thirty-nine".
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