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2528474051 is a prime number
BaseRepresentation
bin1001011010110101…
…0111001111000011
320112012202210100002
42112231113033003
520134242132201
61054521550215
7116441450315
oct22655271703
96465683302
102528474051
111088291a84
125a694536b
13313abb9bc
1419db437b5
15ebea276b
hex96b573c3

2528474051 has 2 divisors, whose sum is σ = 2528474052. Its totient is φ = 2528474050.

The previous prime is 2528474027. The next prime is 2528474129. The reversal of 2528474051 is 1504748252.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-2528474051 is a prime.

It is a super-3 number, since 3×25284740513 (a number of 29 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 2528473996 and 2528474014.

It is not a weakly prime, because it can be changed into another prime (2528471051) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1264237025 + 1264237026.

It is an arithmetic number, because the mean of its divisors is an integer number (1264237026).

Almost surely, 22528474051 is an apocalyptic number.

2528474051 is a deficient number, since it is larger than the sum of its proper divisors (1).

2528474051 is an equidigital number, since it uses as much as digits as its factorization.

2528474051 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 89600, while the sum is 38.

The square root of 2528474051 is about 50283.9343230022. The cubic root of 2528474051 is about 1362.3420664343.

The spelling of 2528474051 in words is "two billion, five hundred twenty-eight million, four hundred seventy-four thousand, fifty-one".