Base | Representation |
---|---|
bin | 1001011011000011… |
… | …1000011101110001 |
3 | 20112021111122211022 |
4 | 2112300320131301 |
5 | 20140011142333 |
6 | 1054553425225 |
7 | 116452342043 |
oct | 22660703561 |
9 | 6467448738 |
10 | 2529396593 |
11 | 1088862109 |
12 | 5a710b215 |
13 | 314052899 |
14 | 19dd03a93 |
15 | ec0d5c98 |
hex | 96c38771 |
2529396593 has 2 divisors, whose sum is σ = 2529396594. Its totient is φ = 2529396592.
The previous prime is 2529396589. The next prime is 2529396691. The reversal of 2529396593 is 3956939252.
2529396593 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2525263504 + 4133089 = 50252^2 + 2033^2 .
It is a cyclic number.
It is not a de Polignac number, because 2529396593 - 22 = 2529396589 is a prime.
It is not a weakly prime, because it can be changed into another prime (2529396523) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1264698296 + 1264698297.
It is an arithmetic number, because the mean of its divisors is an integer number (1264698297).
Almost surely, 22529396593 is an apocalyptic number.
It is an amenable number.
2529396593 is a deficient number, since it is larger than the sum of its proper divisors (1).
2529396593 is an equidigital number, since it uses as much as digits as its factorization.
2529396593 is an evil number, because the sum of its binary digits is even.
The product of its digits is 3936600, while the sum is 53.
The square root of 2529396593 is about 50293.1068139561. The cubic root of 2529396593 is about 1362.5077348606.
The spelling of 2529396593 in words is "two billion, five hundred twenty-nine million, three hundred ninety-six thousand, five hundred ninety-three".
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