Base | Representation |
---|---|
bin | 1110101110010011110… |
… | …1010010011011101111 |
3 | 220011220110212121121101 |
4 | 3223210331102123233 |
5 | 13121020014442303 |
6 | 312111530543531 |
7 | 24163215131554 |
oct | 3534475223357 |
9 | 804813777541 |
10 | 252949374703 |
11 | 98303367103 |
12 | 41034297ba7 |
13 | 1ab1212951c |
14 | c3583daa2b |
15 | 68a6c0cd1d |
hex | 3ae4f526ef |
252949374703 has 2 divisors, whose sum is σ = 252949374704. Its totient is φ = 252949374702.
The previous prime is 252949374673. The next prime is 252949374709. The reversal of 252949374703 is 307473949252.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 252949374703 - 213 = 252949366511 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (252949374709) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 126474687351 + 126474687352.
It is an arithmetic number, because the mean of its divisors is an integer number (126474687352).
Almost surely, 2252949374703 is an apocalyptic number.
252949374703 is a deficient number, since it is larger than the sum of its proper divisors (1).
252949374703 is an equidigital number, since it uses as much as digits as its factorization.
252949374703 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 11430720, while the sum is 55.
The spelling of 252949374703 in words is "two hundred fifty-two billion, nine hundred forty-nine million, three hundred seventy-four thousand, seven hundred three".
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