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25300110119 is a prime number
BaseRepresentation
bin10111100100000000…
…010000101100100111
32102022012121202111112
4113210000100230213
5403303312010434
615342301055235
71553650246664
oct274400205447
972265552445
1025300110119
11a803286219
124aa0b5751b
13250277247b
141320188a6b
159d1203dce
hex5e4010b27

25300110119 has 2 divisors, whose sum is σ = 25300110120. Its totient is φ = 25300110118.

The previous prime is 25300110091. The next prime is 25300110131. The reversal of 25300110119 is 91101100352.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-25300110119 is a prime.

It is a super-2 number, since 2×253001101192 (a number of 22 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 25300110094 and 25300110103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (25300110149) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12650055059 + 12650055060.

It is an arithmetic number, because the mean of its divisors is an integer number (12650055060).

Almost surely, 225300110119 is an apocalyptic number.

25300110119 is a deficient number, since it is larger than the sum of its proper divisors (1).

25300110119 is an equidigital number, since it uses as much as digits as its factorization.

25300110119 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 270, while the sum is 23.

The spelling of 25300110119 in words is "twenty-five billion, three hundred million, one hundred ten thousand, one hundred nineteen".