Base | Representation |
---|---|
bin | 100100110100101010110… |
… | …001110000101111101011 |
3 | 22221220112122112211221002 |
4 | 210310222301300233223 |
5 | 312424332034101011 |
6 | 5214250234505215 |
7 | 350550665136422 |
oct | 44645261605753 |
9 | 8856478484832 |
10 | 2530453425131 |
11 | 896182a98325 |
12 | 34a50389520b |
13 | 15480b9a2c18 |
14 | 8a69042c2b9 |
15 | 45c52452c3b |
hex | 24d2ac70beb |
2530453425131 has 2 divisors, whose sum is σ = 2530453425132. Its totient is φ = 2530453425130.
The previous prime is 2530453425121. The next prime is 2530453425167. The reversal of 2530453425131 is 1315243540352.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 2530453425131 - 26 = 2530453425067 is a prime.
It is a super-2 number, since 2×25304534251312 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (2530453425121) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1265226712565 + 1265226712566.
It is an arithmetic number, because the mean of its divisors is an integer number (1265226712566).
Almost surely, 22530453425131 is an apocalyptic number.
2530453425131 is a deficient number, since it is larger than the sum of its proper divisors (1).
2530453425131 is an equidigital number, since it uses as much as digits as its factorization.
2530453425131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216000, while the sum is 38.
Adding to 2530453425131 its reverse (1315243540352), we get a palindrome (3845696965483).
The spelling of 2530453425131 in words is "two trillion, five hundred thirty billion, four hundred fifty-three million, four hundred twenty-five thousand, one hundred thirty-one".
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