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25305255502493 is a prime number
BaseRepresentation
bin1011100000011110101101…
…10000111110001010011101
310022121011021202122211220112
411300033112300332022131
511304100130402034433
6125453023543255405
75221146551524211
oct560172660761235
9108534252584815
1025305255502493
11807699802a68a
122a083b2a4a565
131117376c53595
14636ad0b16941
152dd3ab33c348
hex1703d6c3e29d

25305255502493 has 2 divisors, whose sum is σ = 25305255502494. Its totient is φ = 25305255502492.

The previous prime is 25305255502489. The next prime is 25305255502511. The reversal of 25305255502493 is 39420555250352.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 18328356632569 + 6976898869924 = 4281163^2 + 2641382^2 .

It is a cyclic number.

It is not a de Polignac number, because 25305255502493 - 22 = 25305255502489 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (25305255502463) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 12652627751246 + 12652627751247.

It is an arithmetic number, because the mean of its divisors is an integer number (12652627751247).

Almost surely, 225305255502493 is an apocalyptic number.

It is an amenable number.

25305255502493 is a deficient number, since it is larger than the sum of its proper divisors (1).

25305255502493 is an equidigital number, since it uses as much as digits as its factorization.

25305255502493 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8100000, while the sum is 50.

The spelling of 25305255502493 in words is "twenty-five trillion, three hundred five billion, two hundred fifty-five million, five hundred two thousand, four hundred ninety-three".